Algorithm
[boj] Cryptographer’s Conundrum_11269 C++
Ruppi
2024. 10. 14. 00:30
문제 캡처
소스 코드
#include <iostream>
#include <string>
using namespace std;
int main() {
string s;
cin >> s;
int count = 0;
for (size_t i = 0; i < s.size(); i += 3) {
string chunk = s.substr(i, 3);
string target = "PER";
for (int j = 0; j < 3; ++j) {
if (chunk[j] != target[j]) {
++count;
}
}
}
cout << count << endl;
return 0;
}