Algorithm

[boj] Cryptographer’s Conundrum_11269 C++

Ruppi 2024. 10. 14. 00:30

문제 캡처

소스 코드

#include <iostream>
#include <string>
using namespace std;

int main() {
    string s;
    cin >> s;
    
    int count = 0;
    for (size_t i = 0; i < s.size(); i += 3) {
        string chunk = s.substr(i, 3);
        string target = "PER";
        for (int j = 0; j < 3; ++j) {
            if (chunk[j] != target[j]) {
                ++count;
            }
        }
    }

    cout << count << endl;
    return 0;
}

Comment…💭